(4x^2+20x+7)/(x+5)

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Solution for (4x^2+20x+7)/(x+5) equation:


D( x )

x+5 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

x in (-oo:-5) U (-5:+oo)

(4*x^2+20*x+7)/(x+5) = 0

4*x^2+20*x+7 = 0

4*x^2+20*x+7 = 0

DELTA = 20^2-(4*4*7)

DELTA = 288

DELTA > 0

x = (288^(1/2)-20)/(2*4) or x = (-288^(1/2)-20)/(2*4)

x = (12*2^(1/2)-20)/8 or x = (-12*2^(1/2)-20)/8

(x-((-12*2^(1/2)-20)/8))*(x-((12*2^(1/2)-20)/8)) = 0

((x-((-12*2^(1/2)-20)/8))*(x-((12*2^(1/2)-20)/8)))/(x+5) = 0

( x-((-12*2^(1/2)-20)/8) )

x-((-12*2^(1/2)-20)/8) = 0 // + (-12*2^(1/2)-20)/8

x = (-12*2^(1/2)-20)/8

( x-((12*2^(1/2)-20)/8) )

x-((12*2^(1/2)-20)/8) = 0 // + (12*2^(1/2)-20)/8

x = (12*2^(1/2)-20)/8

x in { (-12*2^(1/2)-20)/8, (12*2^(1/2)-20)/8 }

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